What is the sum of the geometric series in which a1 = āˆ’5, r = 3, and an = āˆ’405? Hint: cap s sub n equals start fraction a sub one left parenthesis one minus r to the power of n end power right parenthesis over one minus r end fraction comma r ≠ 1, where a1 is the first term and r is the common ratio. (1 point) Sn = āˆ’605 Sn = āˆ’1,220 Sn = āˆ’15 Sn = 605