we have that Find the equation of a line perpendicular to y - 3x = – 8 that passes through the point (3, 2) y - 3x = – 8-----> y=3x-8------> the slope m=3
we know that if two lines are perpendicular then m1*m2=-1 m1=3 so m2=-1/3
with m=-1/3 and point (3, 2) find the equation of the line y=mx+b 2=(-1/3)*3+b------> 2=-1+b-----> b=3
