[tex] {2}^{x + 3} = {8}^{3x + 4} \\ {2}^{x + 3} = {2}^{3(3x + 4)} \\ {2}^{x + 3} = {2}^{9x + 12} \\ x + 3 = 9x + 12 \\ x - 9x = 12 - 3 \\ - 8x = 9 \\ x = - \frac{9}{8} [/tex]
First make sure they have the same base. Once they have the same base, you can solve it like how you normally do
