esmergarciaia20 esmergarciaia20
  • 12-11-2018
  • Mathematics
contestada

ABC has vertices st A(11,6) , B(5,6) , and C(5,17)

Respuesta :

biancamilburn3
biancamilburn3 biancamilburn3
  • 12-11-2018

Distance = ((x2-x1)^2+(y2-y1)^2)^0.5

Solving 

∆ABC  A(11, 6),

B(5, 6), and C(5, 17)


AB = 6 units   BC = 11 units AC = 12.53 units

∆XYZ  X(-10, 5), Y(-12, -2), and Z(-4, 15)

XY = 7.14 units   YZ = 18.79 units XZ = 11.66 units

∆MNO  M(-9, -4), N(-3, -4), and O(-3, -15).



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