Nausicca202
Nausicca202 Nausicca202
  • 11-12-2018
  • Mathematics
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is 2i a real or complex root?

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jimthompson5910 jimthompson5910
  • 11-12-2018

By definition, i = sqrt(-1) because it is used to solve the equation x^2+1 = 0 or x^2 = -1, which has no real number solutions.

Since i is imaginary or complex, then so is 2i

You can express it as 2i = 0+2i to be in the form a+bi with a = 0 as the real part and b = 2 as the imaginary component.

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