Desigurl
Desigurl Desigurl
  • 10-02-2019
  • Mathematics
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PLEASE HELP!!!!!!!!!!!

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5naka
5naka 5naka
  • 11-02-2019
by using identity sin²θ=1 - cos²θ

3sin²θ = 4cosθ - 1

3(1 - cos²θ) = 4cosθ - 1

3 - 3cos²θ = 4cosθ - 1

3cos²θ + 4cosθ - 4 = 0

(3cosθ - 2)(cosθ + 2) = 0

cosθ = ⅔

θ = 48.19° or θ = 311.81°
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