Answer:
For a 470-Ohm resistor connected to a 9-votl battery the current that will flow is 0.019A or 19mA
Explanation:
Ohm's law states that the voltage v along a resistor is directly proportional to the current i flowing through the resistor.
[tex]v = i R[/tex]
Clear i from the equation above
[tex]i = \frac{v}{R}[/tex]
[tex]i = \frac{9volt}{470ohm} =0.019A[/tex]
