Respuesta :

superman1987

Answer:

11.

Explanation:

  • For 0.001 M NaOH:

[OH⁻] = 0.001 M.

∵ pOH = - log[OH⁻]

∴ pOH = - log(0.001 M) = 3.

∵ pH + pOH = 14.

∴ pH = 14 - pOH = 14 - 3 = 11.