Respuesta :

LammettHash

By the law of sines,

[tex]\dfrac{\sin\theta}{2\pi}=\dfrac{\sin110^\circ}{5\pi}\implies\sin\theta=\dfrac{2\sin110^\circ}5[/tex]

[tex]\implies\theta=\sin^{-1}\dfrac{2\sin110^\circ}5\approx22.08^\circ[/tex]

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