Which statement below matches the correct response with the proper reasoning when comparing the volatility of CH2Cl2 with CH2Br2? a. CH2Cl2 is more volatile than CH2Br2 because the dipole-dipole interactions in CH2Cl2 are greater than the dipole-dipole interactions in CH2Br2. b. CH2Cl2 is more volatile than CH2Br2 because of the large dispersion forces in CH2Br2. c. CH2Br2 is more volatile than CH2Cl2because because the dipole-dipole interactions in CH2Br2 are greater than the dipole-dipole interactions in CH2Cl2d. CH2Br2 is more volatile than CH2Cl2 because of the large dispersion forces in CH2Br2

Respuesta :

Answer:

b. CHâ‚‚Clâ‚‚ is more volatile than CHâ‚‚Brâ‚‚ because of the large dispersion forces in CHâ‚‚Brâ‚‚

Explanation:

CH₂Cl₂ is more volatile than CH₂Br₂ (b.p of CH₂Cl₂ = 39,6 °C; b.p of CH₂Br₂ = 96,95°C). Thus, c. and d. are FALSE

Dipole-dipole interactions in CHâ‚‚Clâ‚‚ are greater than the dipole-dipole interactions in CHâ‚‚Brâ‚‚ because Cl is more electronegative that Br (Cl = 3,16; Br = 2,96). But this mean CHâ‚‚Clâ‚‚ is less volatile than CHâ‚‚Brâ‚‚ but it is false.

There are large dispersion forces in CHâ‚‚Brâ‚‚ because Br has more electrons and protons than Cl. Large disperson forces mean CHâ‚‚Brâ‚‚ is less volatile than CHâ‚‚Clâ‚‚ and it is true.

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