Respuesta :
Answer:
a) 48.21 %
b) 45.99 %
c) 20.88 %
d) 42.07 %
e) 50 %
Note: these values represent differences between z values and the mean
Step-by-step explanation:
The test to carry out is:
Null hypothesis  Hâ‚€   is              μ₀ = 30 Â
The alternative hypothesis            m  ≠30
In which we already have the value of z for each case therefore we look  directly the probability in z table and carefully take into account that we had been asked for differences from the mean (0.5)
a)  z = 2.1  correspond to  0.9821  but mean value is ubicated at 0.5 then we subtract   0.9821 - 0.5  and get 0.4821  or 48.21 %
b) Â z = -1.75 Â P(m) = 0.0401 Â Â That implies the probability of m being from that point p to the end of the tail, the difference between this point and the mean so 0.5 - 0.0401 = 0.4599 or 45.99 %
c)  z = -.55   P(m) = 0.2912   and this value  for same reason as before is 0.5 - 0.2912 = 0.2088  or 20.88 %
d)  z = 1.41   P(m) = 0.9207   0.9207 -0.5   0.4207  or  42.07 %
e)  z = -5.3  P(m) = 0   meaning there is not such value in z table is too small to compute  and difference to mean value will be 0.5 Â
d) Â z= 1.41 Â Â Â P(m) =