1. –3g + 2 Â
2. –4λ – 4
Step-by-step explanation:
1. Given data: –7g and 4g + 2
Now, let us find the sum of –7g and 4g + 2.
Sum of –7g and 4g + 2 = (–7g) + (4g + 2)
                   = –7g + 4g + 2
                   = –3g  + 2
2. Given data: 6λ and 2λ – 4
Now, let us find the difference when 6λ is subtracted from 2λ – 4.
6λ subtracted from (2λ – 4) = (2λ – 4) – 6λ
                       = 2λ – 4 – 6λ
                       = –4λ – 4
Hence the sum of –7g and 4g + 2 is –3g + 2 and the difference when 6λ  is subtracted from 2λ – 4 is –4λ – 4.