[tex]\frac{7}{3} \cdot (\frac{2}{3}-\frac{2}{9} )=\frac{7}{3} \cdot (\frac{6}{9} -\frac{2}{9} )=\frac{7}{3} \cdot\frac{4}{9}=\frac{7\cdot4}{3\cdot9}=\frac{28}{27} =1\frac{1}{27}[/tex]
Answer:4/3 =1¹/3
Step-by-step explanation:
using BODMAS
=7/3*(2/3-2/9)
=7/3*2/3-2/9
=14/9-2/9
=12/9
=4/3
=1¹/3
