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A mixture of nitrogen and argon gas is expanded from a volume of to a volume of 62 L to 84 L, while the pressure is held constant at 96 atm . Calculate the work done on the gas mixture. Round your answer to significant digits, and be sure it has the correct sign (positive or negative).

Respuesta :

Explanation:

The given data is as follows.

        P = 96 atm,         [tex]V_{i}[/tex] = 62 L

     [tex]V_{f}[/tex] = 84 L

Now, we know that the relation between work and pressure is as follows.

          W = [tex]-P_{ext}(V_{f} - V_{i})[/tex]

Putting the given values into the above formula we will calculate the work done as follows.

            W = [tex]-P_{ext}(V_{f} - V_{i})[/tex]

                = [tex]-96 (84 - 62)[/tex]

                = -2112 J

or,            = -211.2 kJ     (as 1 kJ = 1000 J)

Thus, we can conclude that the work done on the gas mixture is 211.2 kJ.

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