lakelin12owmqt1 lakelin12owmqt1

11-04-2020
Mathematics

contestada

Please help. I am trying to help my friend

Please help I am trying to help my friend class=

Respuesta :

keziakh004 keziakh004

11-04-2020

Answer:

[tex]log_{10}1100<log_{3}83[/tex]

Step-by-step explanation:

[tex]log_{10} 1100=3.04\\log_{3} 83=4.02[/tex]

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