How would you classify a solution if [OH-] = 4.2 x 10-8 M?

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10-08-2016
Chemistry

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How would you classify a solution if [OH-] = 4.2 x 10-8 M?

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Edufirst Edufirst · Answer 1 · 2016-08-19T22:40:10+02:00

Edufirst Edufirst

19-08-2016

Answer: Slightly acid, almost neutral.

pOH = -log [OH -] = - log [4.2 x 10^-8] = 7.38

pH + pOH = 14 ==> pH = 14 - pOH = 14 - 7.38 = 6.62.

Remember: 7 is neutral, below 7 is acid. This solution is almost neutral.

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warrior7 warrior7 · Answer 2 · 2018-10-05T18:17:15+02:00

warrior7 warrior7

05-10-2018

wrong answer I just took the test

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