10-06-2020
Mathematics

contestada

resuelve las siguientes ecuaciones tales que 0° ≤ x ≤ 360°
sen x=sen (π/2-x)
cos x + 2 sen x= 2
csc x = sec x
2 cos x * tan x -1 = 0
4 cos2 x = 3 - 4 cos x

Respuesta :

abela93 abela93

10-06-2020

Answer:

4cos=2X

X=3-4COS

X=-1

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