calyntanqh calyntanqh
  • 11-07-2020
  • Mathematics
contestada

The HCF of 56, x and 154 is 14 and their LCM is 4312. Find the smallest possible integer x

Respuesta :

PollyP52 PollyP52
  • 11-07-2020

Answer:

Smallest possible x = 98.

Step-by-step explanation:

4312 = 2 * 2 * 2 * 7 * 7 * 11

56 = 2 *2 * 2 * 7

154 = 2 * 7 * 11

Because the HCF is 14:-

x =   = 2 * 7 OR  2 * 7 * other prime number(s).

As there are 2 7's in the prime factors of 4312 there must also be another 7 in the prime factors of x.

x =  2 * 7 * 7 = 98.

Answer Link

Otras preguntas

Jules spent his adolescence just trying to avoid abuse at home. as a result, he never had the inclination to identify his basis beliefes. he finds himself adrif
How do I solve this equation!
write 2 over 8 in simplest form
The believed at the federal government should possess strong powers not specifically
A measure of _______for a numerical data set summarizes all of its values with a single number
Tu (arreglarse) muy bien te arreglas se arreglen arreglar me arreglo nos
In which sentence does the adverb clause modify an adjective? A. I recognized as many flags as he. B. There are specific rules to know before you display the Am
Select another way to show 25 x 18. Mark all that apply! A:20 x 10 plus 20 x 8 plus 5 x 10 plus 5 x 8 B:25 X 20 PLUS 25 X 5 PLUS 25 X 10 PLUS 25 X 8 C: 20 X 18
Can someone help me please
Which equation is in slope intercept form and represents a line with the slope three through the point (9,-4)