Answer:
a). 6 seconds
b). 12 seconds
c). 176.4 meters
Explanation:
a). Equation to be applied to calculate the time taken by the rocket to reach at the peak height,
  v = u - gt
where v = final velocity
u = initial velocity = 58.8 m per sec
g = gravitational pull = 9.8 m per sec²
t = duration of the flight
At the peak height,
v = 0
Therefore, 0 = 58.8 - (9.8)(t)
t = Â [tex]\frac{58.8}{9.8}[/tex]
 = 6 seconds
b). Total time of flight = 2(Time taken to go up)
                  = 2×6
                  = 12 sec
c). Formula to get the peak height is,
  [tex]h=ut-\frac{1}{2}gt^2[/tex]
  h = (58.8)6 - [tex]\frac{1}{2}(9.8)(6)^2[/tex]
   = 352.8 - 176.4
   = 176.4 meters
