Answer:
3<x<5
Step-by-step explanation:
[tex]x^2 - 8x + 15 < 0\\\\\mathrm{Factor}\:x^2-8x+15:\quad \left(x-3\right)\left(x-5\right)\\\left(x-3\right)\left(x-5\right)<0\\\\\mathrm{Find\:the\:signs\:of\:the\:factors\:of\:}\left(x-3\right)\left(x-5\right)\\\\\mathrm{Identify\:the\:intervals\:that\:satisfy\:the\:required\:condition:}\:<\:0\\\\3<x<5[/tex]
