adruschel8
adruschel8 adruschel8
  • 10-11-2020
  • Mathematics
contestada

Solve using the elimination method:
3x + 2y +z = 14
6x + 2y + 6z = 38
x + 2y + z = 18

Respuesta :

gardnerdanj gardnerdanj
  • 11-11-2020

Answer:

x=-2, y=7, and z=6

Step-by-step explanation:

3x + 2y +z = 14

6x + 2y + 6z = 38

x + 2y + z = 18

Take the first and subtract the third.

2x = -4

x = -2

Now the equations become.

2y + z = 20 (both the first and third)

2y + 6z = 50

Subtract the first from the second.

5z=30

z=6

Substitute back.

2y + 6(6) = 50

2y = 14

y=7

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