Respuesta :
Answer:
12) I = 800 kg m/ s ,  13) Δv = 31.25 m / s, 14)  F = -3600 N , 15)  Δv = 4.44 m/s
Explanation:
In this strange exercise you are asked to answer a series of questions
12) force F = 800N applied mass m = 80 kg has a speed change of DV = 10 m / s, calculate the momentum
      I = Δp
      I = m Δv
      I = 80 10
      I = 800 kg m / s
13) a mass of m = 0.80 kg, has an impulse of 25 N s, determines the change in speed
     I = m Δv
     Δv = I / m
     Δv = 25 / 0.8
     Δv = 31.25 m / s
14) a mass m + 1200 kg is carried from 25 m / s to 10 m / s in a period of 5.0 s, determine the force
     I = m ([tex]v_{f}[/tex] -v₀)
the proemd force for this impulse
     I = F t
we substitute
     F t = m (v_{f} -v₀)
     F = m (v_{f} -v₀ / t
     F = 1200 (10-25) / 5
     F = -3600 N
the negative sign indicates that the force is in the opposite direction of the movement
15) a mass = 90 kg with velocity v = 9.0 m has a momentum of I = 400N s, determines the change in velocity
      I = m Δv
      Δv = I / m
      Δv = 400/90
      Δv = 4.44 m / s
if they asked for the final speed it would be.
      I = m (v_{f} -v₀)
      v_{f} = v₀ + I / m
      v_{f} = 9 + 400/90
      v_{f} = 13.4 m / s