Answer:
B.) 0 %
Explanation:
To find out we have to make a punnet square
the mother's genotype XhX
the father's genotype XY
the gametes from the mother Xh and X
the gametes from the father X and Y
       Xh     X
 X      XhX   XX
 Y    XhY    XY
you can see that one of the two daughters has one gene for haemophilia(XhX) but the gene is recessive so she'll be just a carrier