Answer:
Sec <K = 37/12
Step-by-step explanation:
Given the following measure
∠L=90°
LK = 12
KJ = 37, and
JL = 35.
Considering angle K
JL = opposite
KJ =hypotenuse
LK = adjacent
Using SOH CAH TOA identity
Cos theta = adj/hyp
Cos m<K = LK/KJ
cos m<K = 12/37
Since sec theta = 1/cos thets
Sec <K = 1/cos<K
Sec <K = 1/(12/37)
Sec <K = 37/12
