Answer:
[tex]x^{2} -16x +64 = 0[/tex]
Step-by-step explanation:
[tex](x-8)^{2}[/tex] is the same as saying [tex](x-8)(x-8)[/tex]
therefore, you use FOIL(first outside inside last) to get
[tex]x^{2} -8x-8x+64[/tex]
which is [tex]x^{2} -16x +64 = 0[/tex] in standard form
