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Suppose you have a solution that might contain any or all of the following cations: Cu 2, Ag , Ba 2, and Mn2 . The addition of HBr causes a precipitate to form. After the precipitate is filtered off, H2SO4 is added to the supernate, and another precipitate forms. This precipitate is filtered off, and a solution of NaOH is added to the supernatant liquid until it is strongly alkaline. No precipitate is formed. Which ions are present in each of the precipitates

Respuesta :

jufsanabriasa

Answer:

Agāŗ, BaĀ²āŗ,

Explanation:

We can solve this question using the solubility rules:

When an Halide as Br- is added to a solution, the ions that can be precipitate are Agāŗ, Hgā‚‚Ā²āŗ and PbĀ²āŗ.

That means the first ion present is Agāŗ

When sulfates, SOā‚„Ā²ā» are added, the ions that precipitates are: Agāŗ, CaĀ²āŗ, SrĀ²āŗ, BaĀ²āŗ, Hgā‚‚Ā²āŗ and PbĀ²āŗ

The second ion present is BaĀ²āŗ

Hydroxides of CuĀ²āŗ and MnĀ²āŗ are insolubles but as no precipitate are formed when the solution is strongly alkaline those ions are not present.

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