Respuesta :

loneguy

[tex]\text{Given that,}~x^2 +y^2 = 125 ~ \text{and}~ xy =22\\\\(x+y)^2 = x^2 +y^2 +2xy = 125 +2(22) = 169[/tex]

DᴀʀᴋPᴀʀᴀᴅᴏx

[tex]\huge \bf༆ Answer ༄[/tex]

Here's the solution ~

  • [tex] \sf(x + y) {}^{2} [/tex]

  • [tex] \sf {x}^{2} + {y}^{2} + 2xy[/tex]

[ by using formula ]

  • [tex] \sf125 + (2 \times 22)[/tex]

  • [tex] \sf125 + 44[/tex]

  • [tex] \sf169[/tex]

I hope it helps ~

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