kimnjuan127
kimnjuan127 kimnjuan127
  • 12-12-2021
  • Mathematics
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What is the GCF of 14mn, 56m^2n^3, 28m^3n^2?
a) 7m^2n^2
b) 7mn
c) 14m^3n^3
d) 14m^2n^2
e) 14mn

Respuesta :

Аноним Аноним
  • 12-12-2021

Answer:

e) 14mn.

Step-by-step explanation:

The GCF of 14, 56 and 28 is 14,

The GCF of m, m^2 and m^3 is m.

The GCF of n, n^2 and n^3 is n.

The answer is therefore 14mn.

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