Respuesta :
Since H2O is excess, C is limiting reagent and it will decide the amount of H2 formed. Moles of C = 34/12.01 = 2.83. According to stoichiometry, moles of C = moles of H2. Therefore, moles of H2 = 2.83. Mass of H2 formed = moles of H2 formed x molar mass of H2 = 2.83 x 2.016 = 5.70528 grams.Â
Answer:
Correct dimensional analysis is below.
Explanation:
34g    1 mole c     1 mole H2    2.016g H2
___  x  ________  x  ________  x  _________
       12.01g C     1 mole c      1 mole H2
Hope this helps.