what is the value of b^2-4ac for the following equation 10x^2-19x+6=0

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11-02-2017
Mathematics

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what is the value of b^2-4ac for the following equation 10x^2-19x+6=0

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yourdumb yourdumb · Answer 1 · 2017-02-11T09:16:37+01:00

yourdumb yourdumb

11-02-2017

b^2 - 4ac

10x^2 - 19x + 6 = 0

This is for the quadratic formula

Your a value is the scalar of the x^2 (10)
Your b value is the scalar of the x (-19)
Your c value is the constant (6)

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