so we gots apolynomial equation that is 3rd degree and crosses x axis at x=-1, x=0 and x=2
the factors of a poly equation that passes through r1,r2,r3 is (x-r1)(x-r2)(x-r3)
so r1=-1 r2=0 r3=2 f(x)=(x-(-1))(x-0)(x-2) f(x)=(x+1)(x)(x-2) f(x)=x³-x²-2x leading coefient is posiitve because 3rd degree equations that are postive go bottom left to top right yah actually that looks like the exact graph
both f(x)=(x+1)(x)(x-2) and f(x)=x³-x²-2x are correct
