contestada

17. A 60.-kilogram student climbs a ladder a vertical distance of 4.0 meters in 8.0 seconds. Approximately how much total work is done against gravity by the student during the climb?

Respuesta :

work done = change in PE = mgh = 60*10*4 = 2400 J
onyebuchinnaji

The work done against gravity by the student is 2,352 J.

Work done

The work done on an object is the product of applied force and the displacement of the object.

The given parameters:

  • Mass of the student, m = 60 kg
  • Vertical distance, h = 4 m
  • Time of climb, t = 8 s

The work done against gravity by the student is calculated as follows;

W = P.E = mgh

W = 60 x 9.8 x 4

W = 2,352 J

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