joanna93063 joanna93063

10-04-2017
Mathematics

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Solve the following system using the elimination method: 2a+2b=4 and 4a-3b=8

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IcefromTaiwan IcefromTaiwan

10-04-2017

a = 2
b = 0

2a + 2b = 4 → 4a + 4b = 8

(4a + 4b = 8) - (4a - 3b = 8) → 7b = 0

b = 0

so a = 2

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Аноним Аноним

10-04-2017

2a+2b=4 a=1 and b=1

4a-3b=8 a=5 and b=4

hope i helped ya

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