Two cars start out together from the same place. they travel in opposite​ directions, with one of them traveling 5 miles per hour faster than the other. after two ​hours, they are 262 miles apart. how fast is each car​ traveling?

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Annotation
General formula for distance-time-velocity relationship is as following
d = vĀ Ć— t
The velocity of the first car will be v₁, the time is 2 hours, the distance will be d₁.
The velocity of the second car will be vā‚‚, the time is 2 hours, the distance will be dā‚‚.


One of them traveling 5 miles per hour faster than the others. That means the velocity of the first car is 5 miles per hour more than the velocity of the second car.
v₁ = vā‚‚ + 5Ā  (first equation)

The distance of the two cars after two hours will be 262 miles apart. Because they go to opposite direction, we could write it as below.
d₁ + dā‚‚ = 262 (second equation)

Plug the d-v-t relationship to the second equation
d₁ + dā‚‚ = 262
v₁ × t + vā‚‚ Ɨ t = 262
v₁ × 2 + vā‚‚ Ɨ 2 = 262
2v₁ + 2vā‚‚ = 262

Plug the v₁ asĀ Ā (vā‚‚+5) from the first equation
2v₁ + 2vā‚‚ = 262
2(vā‚‚ + 5) + 2vā‚‚ = 262
2vā‚‚ + 10 + 2vā‚‚ = 262
4vā‚‚ + 10 = 262
4vā‚‚ = 252
vā‚‚ = 252/4
vā‚‚ = 63
The second car is 63 mph fast.

Find the velocity of the first car, use the first equation
v₁ = vā‚‚ + 5
v₁ = 63 + 5
v₁ = 68
The first car is 68 mph fast.

Answer
[tex]\boxed{\boxed{ v_{1}=68mph} }[/tex]
[tex]\boxed{\boxed{ v_{2}=63mph} }[/tex]