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General formula for distance-time-velocity relationship is as following
d = vĀ Ć t
The velocity of the first car will be vā, the time is 2 hours, the distance will be dā.
The velocity of the second car will be vā, the time is 2 hours, the distance will be dā.
One of them traveling 5 miles per hour faster than the others. That means the velocity of the first car is 5 miles per hour more than the velocity of the second car.
vā = vā + 5Ā (first equation)
The distance of the two cars after two hours will be 262 miles apart. Because they go to opposite direction, we could write it as below.
dā + dā = 262 (second equation)
Plug the d-v-t relationship to the second equation
dā + dā = 262
vāĀ Ć t + vā Ć t = 262
vāĀ Ć 2 + vā Ć 2 = 262
2vā + 2vā = 262
Plug the vā asĀ Ā (vā+5) from the first equation
2vā + 2vā = 262
2(vā + 5) + 2vā = 262
2vā + 10 + 2vā = 262
4vā + 10 = 262
4vā = 252
vā = 252/4
vā = 63
The second car is 63 mph fast.
Find the velocity of the first car, use the first equation
vā = vā + 5
vā = 63 + 5
vā = 68
The first car is 68 mph fast.
Answer
[tex]\boxed{\boxed{ v_{1}=68mph} }[/tex]
[tex]\boxed{\boxed{ v_{2}=63mph} }[/tex]
General formula for distance-time-velocity relationship is as following
d = vĀ Ć t
The velocity of the first car will be vā, the time is 2 hours, the distance will be dā.
The velocity of the second car will be vā, the time is 2 hours, the distance will be dā.
One of them traveling 5 miles per hour faster than the others. That means the velocity of the first car is 5 miles per hour more than the velocity of the second car.
vā = vā + 5Ā (first equation)
The distance of the two cars after two hours will be 262 miles apart. Because they go to opposite direction, we could write it as below.
dā + dā = 262 (second equation)
Plug the d-v-t relationship to the second equation
dā + dā = 262
vāĀ Ć t + vā Ć t = 262
vāĀ Ć 2 + vā Ć 2 = 262
2vā + 2vā = 262
Plug the vā asĀ Ā (vā+5) from the first equation
2vā + 2vā = 262
2(vā + 5) + 2vā = 262
2vā + 10 + 2vā = 262
4vā + 10 = 262
4vā = 252
vā = 252/4
vā = 63
The second car is 63 mph fast.
Find the velocity of the first car, use the first equation
vā = vā + 5
vā = 63 + 5
vā = 68
The first car is 68 mph fast.
Answer
[tex]\boxed{\boxed{ v_{1}=68mph} }[/tex]
[tex]\boxed{\boxed{ v_{2}=63mph} }[/tex]