amandahorne7686 amandahorne7686

10-03-2018
Chemistry

contestada

What is the molality of a solution that contains 75.2 grams of AgClO4 in 885 grams of benzene? Question 5 options: 0.41 m 4.10 m 8.20 m 0.83 m

Respuesta :

JakeW77 JakeW77

12-03-2018

I took the test and got this question right! Here is the work.

molality = moles solute / kg solvent

moles AgClO4 = 75.2 g / 207.389 g/mol
= 0.3626 mol

molality = 0.6326 mol / 0.885 kg
= 0.410 m
The asnwer is 0.41.

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